MATH SOLVE

4 months ago

Q:
# What is the point slope form of a line with slope 4/5 that contains the points -2,1

Accepted Solution

A:

y - y1 = m(x - x1)

slope(m) = 4/5

(-2,1)....x1 = -2 and y1 = 1

now we sub

y - 1 = 4/5(x - (-2) =

y - 1 = 4/5(x + 2) <===

slope(m) = 4/5

(-2,1)....x1 = -2 and y1 = 1

now we sub

y - 1 = 4/5(x - (-2) =

y - 1 = 4/5(x + 2) <===