Find the equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1, 3).

Answer:Step-by-step explanation:for two lines to be parallel they MUST have the same slope but have different Y intercepts ( Y axis crossing values)parallel lines will never intersect each otherfirst I use a graphing calcuator to solve the problemI like to use y intercept form better, but you don't have use it I will try to solve it directly without going through the y intercept equationx + 5y = 10    in y intercept form y = mx + b is 5y = -x + 10     divide both sides by 5y = -x/5 + 10/5     y = -x/5 + 2 Now I need to find a parallel line that passes through the x =1 and y = 3 point recall this line will have the same slope =     m = -1/5 and a different Y axis crossing point 'b' that we don't knowy = -x/5 + b      y = 3 when x = 1 so slove for 'b'3 = -1/5 + b3 = -0.2 + b    add -0.2 to both sides3.2 = by = -x/5 + 3.2     this is answer in y intercept form                           if you multiply both sides by 55y = -x + 16        add x to both sidesx + 5y = 16         answer in standard formTHE EASIER WAY TO SOLVE THE PROBLEM IS ......x + 5y = 10      find a line parallel that passes through x  = 1,  y = 3  x + 5y = Z       Z is an unknown value  plug in x and y and solve for Z1 + 5(3) = ZZ = 16              so the parallel line in standard form isx + 5y = 16     same as before,  my y intercept method was correct, but not  worth the effort